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MYTH:
Clean
water! A wonderful dream :))))
If you ignore
the method of imploding the Brown's Gas over the
contaminated water (this would cause an
explosion) and use instead a separate chamber to
implode the Brown's Gas, then allow the already
existing water vapor in the contaminated chamber
to be sucked into the Brown's Gas container, to
be condensed - YES it will work! BUT the
electricity required to produce enough vacuum by
this method would be much better spent driving a
conventional vacuum pump. You'd get several
times more water without the possibility of
explosion.
• See
For Yourself:
Let's do some
math. We'll assume we have excluded all air from
a container containing contaminated water and
that container is at 20°C. Water vapor in
the contaminated container would be at a
pressure of 0.02 kp/cm2 and would contain
0.01729 kg/m3. One liter of water turned to pure
Brown's Gas would occupy about 3.7 m3 of volume.
We introduce the water vapor to the vacuum
created by the imploded Brown's Gas; which at
.01 kp/cm2 and 20°C, water vapor density is
0.0072516 kg/m3. Thus, one liter of Brown's Gas
(imploded) would recover a maximum of 0.037
liters of water (less because Brown's Gas water
already occupies volume and as gas from the
contaminated tank rushes into the Brown's Gas
tank, Brown's Gas tank pressure
rises).
Each liter of
water takes about 10,800,000.00 joules to create
3700 liters of Brown's Gas, recovering a maximum
of 0.037 liters of water. Assuming temperatures
remain the same. If we assume this process took
one hour, then we use a constant of 3 Kwh to
purify 37 grams of water per hour using this
Brown's Gas technique.
• If We
Use A Simple Vacuum Pump:
we move water
vapor from an environment of 0.01 kp/cm2 to 1
kp/cm2 (vacuum to atmospheric pressure).
Increased pressure at the same temperature
causes the excess moisture to condense out. The
moisture holding capacity of vapor per cubic
meter is fixed by temperature, not pressure.
Thus pumping 3.7 m3 to atmospheric pressure
recovers about 0.024 liters of water. Our pump
would use about 0.1 Kwh of power.
• If We
Use A Simple Evaporation System:
working at
atmospheric pressure and heating the
contaminated water (with solar is best, but
we'll assume using electric) to 30°C, then
we could recover 0.024 liters of water with 0.02
Kwh of power.
• Does
It Make Sense To You?
Why purify water
with Brown's Gas when a simple evaporation
system is simplest and least expensive to
operate? The evaporation system is simple and
inexpensive to build, is not dangerous and uses
only a very tiny fraction of the power used by
the Brown's Gas technique. Of course,
evaporation systems using solar power do require
some space and are not really
portable.
• Are
You Starting To Get A Picture
Here?
Yes, Brown's Gas
can do a lot of things, but can it do those
things in a more practical manner than other
(already existing) options?
At
Eagle-Research we dispel myths, and we also find
practical uses, see Fabulous
Uses
:))
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